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Xiu Zhang

TechNet Community Support

 
  • Thursday, December 29, 2011 9:28 PM
     
     
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    So the command I tried was:

    [PS] D:\>Get-transportserver | Get-MessageTrackingLog -resultsize unlimited -Start "12/29/2011 8:00:00 AM" | where-object {} | select Send
    er, RecipientCount, MessageSubject | Sort-Object -Unique MessageSubject | ft -AutoSize

    Unfortunately it appears to only return the recipient count from the last e-mail with the same subject.

    So, if a user sends out a bulk e-mail with the subject "Important Information" to list A that has 1,200 recipients and then sends out the same e-mail with subject "Important Information to list B that has 6 recipients, this command will only show the 6 recipients.

    Thank you Xiu for the input though, I was not familiar with the "-unique" tag for sort-object.

     


    Jason Meyer
     
  • Thursday, January 05, 2012 2:19 AM
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    Hi,

    Thus more research need to be done.

    Any update I will post here.


    Xiu Zhang

    TechNet Community Support

     
  • Sunday, January 08, 2012 3:02 PM
     
     
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    Can you just please clarify something for me? You want how many recipients a user sent e-mails to in a day, right? But do you want unique recipients? Is enough to sum the RecipientCount per each e-mail they send?
    div>
     
  • Sunday, January 08, 2012 3:11 PM
     
     
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    If you don't care about unique recipients and I only send two e-mails today to the same recipient, this will output 2:

    ForEach ($email in (Get-TransportServer | Get-MessageTrackingLog -ResultSize Unlimited -Start "01/08/2012" -Sender user@domain.com -EventId RECEIVE | ? {} | Select RecipientCount)) {}
    
    $total
    

    If you just want unique recipients, this will output 1:

    [String] $total = $null
    
    ForEach ($email in (Get-TransportServer | Get-MessageTrackingLog -ResultSize Unlimited -Start "01/08/2012" -Sender user@domain.com -EventId RECEIVE | ? {} | Select Recipients)) {}
    
    $total2 = $total.Split(" ")
    
    ($total2 | sort -Unique).Count - 1
    


    div>
     
  • Sunday, January 15, 2012 6:14 PM
     
     
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